Can You Help Solve This Generalized Work Problem with an Illustrative Image?

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SUMMARY

The discussion centers on solving a generalized work problem involving energy conservation principles. The user successfully derived the equation for part (a) using the formula Ki + Ui + Wext = Kf + Uf, leading to V = √2g(h1 - h2 - LμCosΘ). For parts (b) and (c), the user acknowledges the need to incorporate spring energy at maximum compression. The collaborative nature of the forum facilitated the user's understanding and resolution of the problem.

PREREQUISITES
  • Understanding of energy conservation principles in physics
  • Familiarity with potential and kinetic energy equations
  • Knowledge of spring mechanics and energy storage
  • Basic trigonometry for expressing h1 - h2 in terms of L and θ
NEXT STEPS
  • Research the concept of spring potential energy and its calculations
  • Explore advanced applications of energy conservation in mechanical systems
  • Learn about the role of friction in energy loss during motion
  • Study the derivation and application of kinematic equations in physics
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in solving mechanical work problems involving energy conservation and spring dynamics.

Ced
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Homework Statement
A crate of mass(m) is above a ramp of angle theta and a distance(L) from a spring of constant k. The ramp and the crate have a coefficient of kinetic friction(μ)
a.) What is the crate's speed before it compresses the spring
b.) What is the maximum compression of the spring
c.) How far does the box get to its initial distance once it rebounds.
Relevant Equations
I think the relevant equations are
1. Ki + Ui + Wext = Kf + Uf
2. Elastic energy U=\frac{1}{2} k \Delta x^{2}
Here is an image for better illustration,
Capture.JPG


I only managed to solve for (a) but I'm not sure if I did it right. As for (b) and (c), I have no idea how to do it.

My answer for (a):
=> Ki + Ui + Wext = Kf + Uf
=> 0+mgh1-LμmgCosΘ = 1/2mv^2 + mgh2
=>1/2v^2 = gh1- gh2 - LμgCosΘ
=> V = √2g(h1 - h2 - LμCosΘ)
 
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You can express h1 - h2 in terms of L and theta. Part b will have a term for the spring energy at maximum compression on the final side.
 
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Zexuo said:
You can express h1 - h2 in terms of L and theta. Part b will have a term for the spring energy at maximum compression on the final side.
Thank you so much! I got the answer now. You helped me a lot!
 

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