Can You Help Solve This Generalized Work Problem with an Illustrative Image?

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The discussion revolves around solving a generalized work problem using an illustrative image. The user successfully solved part (a) of the problem but expressed uncertainty about parts (b) and (c). The solution for (a) involves energy conservation principles, leading to a formula for velocity in terms of height and friction. Additional guidance was provided regarding the inclusion of spring energy in part (b). Ultimately, the user received the necessary help to arrive at the correct answer.
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Homework Statement
A crate of mass(m) is above a ramp of angle theta and a distance(L) from a spring of constant k. The ramp and the crate have a coefficient of kinetic friction(μ)
a.) What is the crate's speed before it compresses the spring
b.) What is the maximum compression of the spring
c.) How far does the box get to its initial distance once it rebounds.
Relevant Equations
I think the relevant equations are
1. Ki + Ui + Wext = Kf + Uf
2. Elastic energy U=\frac{1}{2} k \Delta x^{2}
Here is an image for better illustration,
Capture.JPG


I only managed to solve for (a) but I'm not sure if I did it right. As for (b) and (c), I have no idea how to do it.

My answer for (a):
=> Ki + Ui + Wext = Kf + Uf
=> 0+mgh1-LμmgCosΘ = 1/2mv^2 + mgh2
=>1/2v^2 = gh1- gh2 - LμgCosΘ
=> V = √2g(h1 - h2 - LμCosΘ)
 
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You can express h1 - h2 in terms of L and theta. Part b will have a term for the spring energy at maximum compression on the final side.
 
Zexuo said:
You can express h1 - h2 in terms of L and theta. Part b will have a term for the spring energy at maximum compression on the final side.
Thank you so much! I got the answer now. You helped me a lot!
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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