Can You Help Verify This Calculus Derivative Solution?

[Jake Minneman]

Hello, I am fourteen and "attempting" to teach myself calculus I was wondering if anyone with prior calculus knowledge would be willing to solve this derivative in order to check my answer.d
---- (x^3-x^2)+(3x)
dx
(My thought process)

d-----------------d
=--- (x^3-x^2)+---(3x)
dx---------------dx

=3x^(3-1)-2x^(3-1)+3x

=3x^2-2x+3

=3x^2-2x+3Sorry if I screwed that up.

 

[vela]

I wouldn't worry too much about embarrassing yourself. Everyone here had to learn this stuff at some time and probably made the same kinds of mistakes as everybody else.

You can use www.wolframalpha.com to find derivatives. Just enter "derivative of (x^3-x^2)+(3x)".

 

[Jake Minneman]

Thanks for the help

 

[vela]

You have a couple of typos in your work, but your method and final answer are correct.

 

[Jake Minneman]

Thanks for the help

Yes I got it

 

[Mark44]

Hello, I am fourteen and "attempting" to teach myself calculus I was wondering if anyone with prior calculus knowledge would be willing to solve this derivative in order to check my answer.


d
---- (x^3-x^2)+(3x)
dx
(My thought process)

d-----------------d
=--- (x^3-x^2)+---(3x)
dx---------------dx

=3x^(3-1)-2x^(3-1)+3x

In the line above, it should be
=3x^(3-1)-2x^(2[/color]-1)+3[STRIKE]x[/STRIKE]

=3x^2-2x+3

=3x^2-2x+3


Sorry if I screwed that up.

 

[Jake Minneman]

In the line above, it should be
=3x^(3-1)-2x^(2[/color]-1)+3[STRIKE]x[/STRIKE]

Thank you the typing of the question has been giving me trouble.

 

[Mark44]

You might want to look into how to format things using LaTeX. You can click any of the lines below to see what I did.
$$\frac{d}{dx}(x^3 - x^2 + 3x)$$
$$=\frac{d}{dx}x^3 - \frac{d}{dx}x^2 + \frac{d}{dx}3x$$
$$=3x^{3 -1} - 2x^{2 -1} + 3x^{1 - 1}$$
$$=3x^2 - 2x + 3$$

 

[Jake Minneman]

You might want to look into how to format things using LaTeX. You can click any of the lines below to see what I did.
$$\frac{d}{dx}(x^3 - x^2 + 3x)$$
$$=\frac{d}{dx}x^3 - \frac{d}{dx}x^2 + \frac{d}{dx}3x$$
$$=3x^{3 -1} - 2x^{2 -1} + 3x^{1 - 1}$$
$$=3x^2 - 2x + 3$$

This helped tremendously

 

[Mark44]

Glad to hear it!

There are a few LaTeX tags that I use a lot.
Integral - [ tex] \int f(x) dx [ /tex]
Definite integral - [ tex] \int_{a}^{b} f(x) dx [ /tex]
Fraction or rational expression - [ tex] \frac{x + 2}{x^2 - 4}[ /tex]
Limit - [ tex] \lim_{x \to 0} f(x) [ /tex]

If you remove the extra spaces I added in the tex tags, the expressions above render like this:

$$\int f(x) dx$$
$$\int_{a}^{b} f(x) dx$$
$$\frac{x + 2}{x^2 - 4}$$
$$\lim_{x \to 0} f(x)$$

 

[Jake Minneman]

thats sweet