Can You Integrate f(x)=40*e^(-0.5x) Using the u-Substitution Method?

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SUMMARY

The discussion focuses on integrating the function f(x)=40*e^(-0.5x) using the u-substitution method. The key insight provided is that by differentiating e^(-0.5x), one can derive the necessary components for integration. The suggested substitution is u = -0.5x, leading to du = -0.5dx, which simplifies the integration process. This method is a standard approach for integrating exponential functions.

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  • Familiarity with the u-substitution method in calculus
  • Basic knowledge of differentiation techniques
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chevy900ss
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f(x)=40*e^(-0.5x)
 
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If anyone could help my figure it out i would really appreciate it. Thanks
 
Welcome to PF!

Hi chevy900ss! Welcome to PF! :smile:

(try using the X2 tag just above the Reply box :wink:)

(btw, really bad idea to answer your own thread … people are much more likely to reply to unanswered threads!)
chevy900ss said:
f(x)=40*e^(-0.5x)

Hint: what do you get if you differentiate e-0.5x ? :smile:
 
If you cannot answer tiny-tim's question, in general, you can integrate eax by making the substitution u= ax so du= adx, (1/a)du= dx.
 

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