Can You Integrate f(x)=40*e^(-0.5x) Using the u-Substitution Method?

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Discussion Overview

The discussion revolves around the integration of the function f(x)=40*e^(-0.5x) using the u-substitution method. Participants explore the steps and techniques involved in performing this integration, with a focus on the application of substitution in calculus.

Discussion Character

  • Homework-related
  • Mathematical reasoning

Main Points Raised

  • One participant presents the function f(x)=40*e^(-0.5x) as the subject of integration.
  • Another participant expresses a need for assistance in solving the integration problem.
  • A welcome message includes a hint regarding the differentiation of e^(-0.5x), suggesting it may be relevant to the integration process.
  • A further contribution outlines a general method for integrating functions of the form e^(ax) by proposing a substitution u=ax, leading to du=adx.

Areas of Agreement / Disagreement

The discussion does not reach a consensus, as participants are still exploring the integration process and have not provided definitive solutions or agreements on the method.

Contextual Notes

Participants have not fully elaborated on the assumptions or specific steps involved in the integration process, leaving some mathematical details unresolved.

chevy900ss
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f(x)=40*e^(-0.5x)
 
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If anyone could help my figure it out i would really appreciate it. Thanks
 
Welcome to PF!

Hi chevy900ss! Welcome to PF! :smile:

(try using the X2 tag just above the Reply box :wink:)

(btw, really bad idea to answer your own thread … people are much more likely to reply to unanswered threads!)
chevy900ss said:
f(x)=40*e^(-0.5x)

Hint: what do you get if you differentiate e-0.5x ? :smile:
 
If you cannot answer tiny-tim's question, in general, you can integrate eax by making the substitution u= ax so du= adx, (1/a)du= dx.
 

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