Can You Integrate f(x)=40*e^(-0.5x) Using the u-Substitution Method?

[chevy900ss]

f(x)=40*e^(-0.5x)

 

[chevy900ss]

If anyone could help my figure it out i would really appreciate it. Thanks

 

[tiny-tim]

Welcome to PF!

Hi chevy900ss! Welcome to PF!

(try using the X² tag just above the Reply box )

(btw, really bad idea to answer your own thread … people are much more likely to reply to unanswered threads!)

f(x)=40*e^(-0.5x)

Hint: what do you get if you differentiate e^-0.5x ?

 

[HallsofIvy]

If you cannot answer tiny-tim's question, in general, you can integrate e^ax by making the substitution u= ax so du= adx, (1/a)du= dx.