Can You Integrate f(x)=40*e^(-0.5x) Using the u-Substitution Method?

  • Thread starter Thread starter chevy900ss
  • Start date Start date
  • Tags Tags
    Integrate
chevy900ss
Messages
16
Reaction score
0
f(x)=40*e^(-0.5x)
 
Physics news on Phys.org
If anyone could help my figure it out i would really appreciate it. Thanks
 
Welcome to PF!

Hi chevy900ss! Welcome to PF! :smile:

(try using the X2 tag just above the Reply box :wink:)

(btw, really bad idea to answer your own thread … people are much more likely to reply to unanswered threads!)
chevy900ss said:
f(x)=40*e^(-0.5x)

Hint: what do you get if you differentiate e-0.5x ? :smile:
 
If you cannot answer tiny-tim's question, in general, you can integrate eax by making the substitution u= ax so du= adx, (1/a)du= dx.
 
For original Zeta function, ζ(s)=1+1/2^s+1/3^s+1/4^s+... =1+e^(-slog2)+e^(-slog3)+e^(-slog4)+... , Re(s)>1 Riemann extended the Zeta function to the region where s≠1 using analytical extension. New Zeta function is in the form of contour integration, which appears simple but is actually more inconvenient to analyze than the original Zeta function. The original Zeta function already contains all the information about the distribution of prime numbers. So we only handle with original Zeta...
Back
Top