Can You Solve These Physics Puzzles Before Tomorrow's Deadline?

[emjez15]

guyz, i have this problems.. due tomorrow, pls help me pls.. thank you so much

1. A Russian Balloonist floating at an altitude of 150m accidentally drops his samovar & starts to ascend at the constant velocity of 1.2m/s. How high will the balloons be when the samovar reaches the ground?

2. An orangutan throws a coconut vertically upward at the foot of a cliff 40m high while his make simultaneously drops another coconut from the top of the cliff. The two coconuts collide at an altitude of 20m. What was the initial velocity of the coconut that was thrown upward?

3. A ball is thrown at 20m/s from the roof of a building 25m high at an angle of 30o below the horizontal. At what height above the ground will the ball strike the side of another building 20m away from the first?

 

[Integral]

Tell us what you know.

 

[emjez15]

thank God I've got it

thanks anyways,

here's the answers

1. A Russian Balloonist floating at an altitude of 150m accidentally drops his samovar & starts to ascend at the constant velocity of 1.2m/s. How high will the balloons be when the samovar reaches the ground?

s=150m
a=9.8
s=0.5at^2
300=9.8t^2
t=5.5328...sec
moving at 1.2m/s
therefore
s=vt
s=6.64m upwards
He is at 156.64m when it reaches the ground

2. An orangutan throws a coconut vertically upward at the foot of a cliff 40m high while his make simultaneously drops another coconut from the top of the cliff. The two coconuts collide at an altitude of 20m. What was the initial velocity of the coconut that was thrown upward?

They collide at 20m, in the middle
for the coconut at the top
s=20
a=9.8
v^2 = u^2 + 2as
v = sqrt(392)
when they make contact
v = u+at
sqrt(392) = 9.8t
t = 2.0203...sec
therefore the one at the bottom must have covered 20m in 2.0203...sec
v=s/t
v=9.90m/s (3sf)

Sir Abente PROJECTILE September 4, 2008

3. A ball is thrown at 20m/s from the roof of a building 25m high at an angle of 30o below the horizontal. At what height above the ground will the ball strike the side of another building 20m away from the first?

Horizontal component 20cos30

Vertical component 20sin30

s=20m
v=20cos30
v=s/t
t=s/v
t=1.1547...sec

u=20sin30m/s
t=1.1547...sec
a=-9.8m/s/s
s=ut+0.5at^2
s=5.01m
It will move up 5.01m
Therefore it will hit the building at 30.01m

 

[emjez15]

@Integral

you should've help if i we're you, dude..:)

 

[LowlyPion]

@Integral

you should've help if i we're you, dude..:)

The rules are that you have to show your work and others may help you as to where you may be going wrong.

The idea is helping you to learn to do your homework, not to help you do your homework by actually doing it for you.

Looks like he helped you after all.

 

[emjez15]

, who's he?.. my uncle teach me,,

i mean that you should've give me some formula or something, I am not asking directly for the answers..

Please read my post first

 

[LowlyPion]

, who's he?.. my uncle teach me,,

i mean that you should've give me some formula or something, I am not asking directly for the answers..

Please read my post first

I did review your first post and you showed no work. No formulas. No approach. Integral's response to you was what I would have said if I had responded to you first.

You've shown your work and indicated that you are satisfied with the results. Not sure what you want at this point.