Physics gr11 review (acceleration)

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SUMMARY

The forum discussion focuses on solving physics problems related to acceleration and free fall, specifically for Grade 11 students. Key problems include calculating the speed of a train's last car, the time for a dropped can to reach the ground, the distance between two stones dropped at different times, and the height of a cliff based on sound travel time. The equations used include kinematic formulas such as Vf^2=V1+2ad and d=V1+1/2at^2. The solutions provided indicate varying levels of understanding, with some calculations needing verification.

PREREQUISITES
  • Understanding of kinematic equations in physics
  • Basic knowledge of acceleration and free fall concepts
  • Familiarity with units of measurement (meters, seconds)
  • Ability to solve algebraic equations
NEXT STEPS
  • Review kinematic equations and their applications in physics problems
  • Practice solving problems involving free fall and acceleration
  • Explore the concept of relative motion in physics
  • Learn about sound waves and their properties, particularly in relation to distance and time
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Grade 11 physics students, educators teaching kinematics, and anyone preparing for exams involving motion and acceleration concepts.

justme_girl04
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1. The problem statements, all variables and given/known data

1. a 100m long train accelerates uniformly from rest. If the front of the train passes a railway worker 150m down the track at a speed of 25m/s, what will be the speed of the last car as it passes the worker?

2. a hot air balloon is rising up with a constant velocity of 4m/s. As the balloon reaches a height of 4m above the ground the balloonist accidentally drops a can of pop over the edge of the basket. How long does it take the pop can to reach the ground?

3.a stone is dropped from the roof of a high building. a second stone is droped 1s later. How far apart are the stones when the second one reached the speed of 23m/s?

3. a rock is dropped from a seacliff and the sound of it stirking the ocean is heard 3s later. If the speed of sound is 330m/s, how high is the cliff?



Homework Equations


These are the equations we were given to solve the questions:
(it might look messy, f is final and t is time)
Vf^2=V1+2ad
Vf=V1+at
d=V1+1/2at^2
d=Vft-1/2at^2
d=(V1+Vf/2)t

honestly i tried doing these, but i just don't get it!
 
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1. 150/25 = 250/x
x = 41.6666667m/s

2. this one is weird. can't help. are you sure you copied all the data?

3. vf^2=vi+2ad
23^2=0+2(9.8)d
d=27 m (stone 1)

d = (vi+vf/2)t
27 = (0+ 27/2)t
t=2 seconds( the first stone reached 27m in two seconds)

2s -1s = 1s so we want to calculate the position of stone 2 at one seconds so

d = vi + .5at^2
d = 0 + .5*9.8*1^2
d = 4.9m

21 - 4.9 = 22.1m difference

4. 3s * 330m / 1s = 990 m

have no clue if any of these are correct. please check my work guys
 
Hey thanks for the help, the first and third make sense.. yea it know the second is weird but i read the question over and that's what it says. the 4th one is way off lol, it was a pretty long solution that came to a heights of h=4.9(2.9)^2
 

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