- #1
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So, let G be a nonempty finite set with an associative binary operation such that for all a,b,c in G ab = ac => b = c & ba = ca => b = c, i.e. both left and right cancellation hold. The G is a group.
Ok, I really had no inspiration how to solve this one, so I looked at the solution, which confused me. Namely, it states that, given any element a from G, the set <a> = {a^k : k in N} must be a subset of G, and even better, it is a closed subset of G, and we *consider it in place of G*. This is what confuses me. How can we consider it in place of G? What if there are other elements in G which can not be generated by some a from G? I'm probably missing something simple, but I can't figure it out.
Thanks in advance.
Ok, I really had no inspiration how to solve this one, so I looked at the solution, which confused me. Namely, it states that, given any element a from G, the set <a> = {a^k : k in N} must be a subset of G, and even better, it is a closed subset of G, and we *consider it in place of G*. This is what confuses me. How can we consider it in place of G? What if there are other elements in G which can not be generated by some a from G? I'm probably missing something simple, but I can't figure it out.
Thanks in advance.