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CANDU Reactor contains 70 kf og fissionable material

  • Thread starter JohnTralp
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  • #1
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Homework Statement





Homework Equations



Working at a rate of 1.204 x 10^22 fissions/s, what fraction of that 70 kg mass of Uranium will be fissioned during the 550 days of fuel installation? (Fuel rods are replaced appx. every year and a half)

The Attempt at a Solution



1.20x10^22 fissions/s = 1.0368 fissions/day

550 days = 5.7x10^29 fissions

5.7x10^29 fissions = 225376210.5 grams

225376210.5 grams / 70 000 grams = 3219.66%. Which is incorrect.
 
Last edited:

Answers and Replies

  • #2
phyzguy
Science Advisor
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The initial value of 1.2x10^22 fissions/s can't be right. At ~ 200MeV/fission, this is about 400 GW.
 

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