Cant remember how to use formula

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Discussion Overview

The discussion revolves around the use of formulas related to the slope of a line and the equation of a line in the context of algebra. Participants are seeking clarification on the correct application of these formulas, particularly the relationship between the slope (m), the y-intercept (c), and the coordinates of points on the line.

Discussion Character

  • Homework-related, Technical explanation

Main Points Raised

  • One participant questions their understanding of the formula for the slope (m) and its application in the equation of a line, specifically asking whether c is equal to -y or /y.
  • Another participant confirms the formula for the slope as m = (y2 - y1) / (x2 - x1) and states that c can be expressed as c = y1 - mx1.
  • A third participant reiterates the equation of the line and clarifies that c is not equal to (m)(x), suggesting that the original question lacks clarity.
  • A later reply provides another expression for c as c = -mx1 + y1, reinforcing the relationship between the slope and the y-intercept.

Areas of Agreement / Disagreement

Participants express differing views on the interpretation of the relationship between c, m, x, and y. There is no consensus on the original question posed regarding the formula.

Contextual Notes

Some participants' responses depend on the correct interpretation of the variables involved, and there may be assumptions about the familiarity with the concepts of slope and line equations that are not explicitly stated.

lostit
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Cant remember how to use formula !

i can't for the life of me remember which way to do this formula someone please show me the light,,,,,
to find the slope(m) of the line you have y2 - y1 / x2 - x1 am i right then getting the result (m) you use this formula y=mx+c
taking y1 for y and x1 for x ,
now here's my question
we have c = (m)(x) is it - y or is it /y

thanks for your replys in advance..
 
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[tex]m = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex] [tex]y = mx+c[/tex] then [tex]c = y_1-mx_1[/tex]
 
Last edited:
y=mx + c is the equation of the line. Here x and y are coordinates of any point on that line.
(y2-y1)/(x2-x2) will give you the slope m. Here x1 y1, x2 y2 are coordinates of two particular points.
Your question makes no sense, as c is not equal to (m)(x)
 
courtrigrad said:
[tex]m = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex] [tex]y = mx+c[/tex] then [tex]c = y-mx[/tex]

[tex]c = -mx_{1}+y_{1}[/tex].
 

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