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Can't seem to get the correct acceleration

  1. Sep 8, 2008 #1
    From a position vs. time graph I calculated the slope of 2 tangent lines which is the velocity. The first slope was 390 cm/sec and the second slope was 486 cm/sec. Now to get the acceleration I thought I take difference of the velocities divided by the time interval 0.9 (1/60 sec) or 0.015sec. After calculations I got an acceleration of 6,400 cm/sec^2 which would be 64m/s^2. The only thing is that the acceleration should be close to 9.80m/s^2 because it was a free falling object and I need to find percent error. What am I doing wrong because I should be getting around 9.80m/s^2 and not such a large number like 64.
     
  2. jcsd
  3. Sep 9, 2008 #2

    Kurdt

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    It might help if you could post the graph you're working from. From working out the difference of the slopes one gets an answer of 96 which would get you a reasonable answer if the time interval was 0.1s. Are you sure you're reading the graph scale correctly?
     
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