Cant understand similar proof Quantum numbers from PDE (pdf attachment)

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SUMMARY

This discussion centers on the understanding of quantum numbers derived from the Schrödinger equation, specifically addressing the roles of the quantum numbers n, l, and m. The user expresses confusion regarding the appearance of +n² and the negative values of l and m in the context of partial differential equations (PDEs). Key points include the application of the superposition principle in linear equations and the reasoning behind the use of cosh and sinh functions in certain solutions, as opposed to sine and cosine. The discussion also clarifies that when ℓ approaches 0, sine is approximated by x, reflecting first-order approximations of trigonometric functions.

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  • Understanding of the Schrödinger equation and its implications in quantum mechanics.
  • Familiarity with partial differential equations (PDEs) and their solutions.
  • Knowledge of linear algebra, particularly the superposition principle in linear equations.
  • Basic concepts of trigonometric functions and their approximations.
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  • Study the derivation of quantum numbers from the Schrödinger equation in detail.
  • Explore the role of partial differential equations in quantum mechanics, focusing on solutions involving cosh and sinh.
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  • Examine the Taylor series expansion to understand the approximation of trigonometric functions near zero.
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Students and professionals in physics, particularly those studying quantum mechanics and partial differential equations, as well as educators looking to clarify concepts related to quantum numbers and their mathematical foundations.

mohsin031211
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I believe that this is similar to the proof of Schrödinger equation to obtain quantum numbers, however i cannot seem to understand the relationship between n, l and m:

I have attached a pdf file on partial differential equations and on page 5, i cannot seem to understand why it is +n^2 and l,m are negative?

Also, on page 6 it states 'Hence the sumis also a solution. Note ℓ and m do not have to be integers and so
the above need not be a discrete sum. Also note that if ℓ → 0, cosine is replaced
by 1 and sine by x.' why is sine replaced by x, shouldn't it disappear as it equals to 0 rather than being replaced by x?

My final query is about equation 1.28, how the superposition principle is applied? Does it just form linear equations of the solutions and why is the solution for equation 1.27 cosh and sinh whereas for the rest it isn't?

Thank you so much in advance , whoever can clear this for me
 

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mohsin031211 said:
I have attached a pdf file on partial differential equations and on page 5, i cannot seem to understand why it is +n^2 and l,m are negative?
He knows that X''(x)/X(x) is equal to some real number for all x, so he needs to pick a notation for that number. He chooses -l^2 because it makes the solutions look nice: \cos lx and \sin lx.

He knows that each term of (1.20) is a real number, and that they add up to 0. So they can't all have the same sign. He's showing you how to proceed if the first two happen to be non-positive and the third non-negative. That's why the Z equation has sinh and cosh solutions instead of sin and cos solutions.

mohsin031211 said:
Also note that if ℓ → 0, cosine is replaced
by 1 and sine by x.' why is sine replaced by x, shouldn't it disappear as it equals to 0 rather than being replaced by x?
I don't see what that limit has to do with anything, but 1 and x are the first-order approximations of cos x and sin x respectively. Recall that f(x)=f(0)+xf'(0)+... But maybe he's not talking about that at all. If you just set l=0 in (1.21), the X equation becomes X''(x)=0. It has x and 1 as solutions (actually, any first-degree polynomial). Maybe that's what he meant.

mohsin031211 said:
My final query is about equation 1.28, how the superposition principle is applied? Does it just form linear equations of the solutions and why is the solution for equation 1.27 cosh and sinh whereas for the rest it isn't?
The superposition principle is the idea that if f and g are solutions, then so is af+bg where a and b are real numbers. I don't like calling it a "principle", because it follows from the fact that we're dealing with linear equations. Consider X''(x)+l^2X(x)=0. If we denote the operator that takes a function to its derivative by D, then the equation can be written as (D^2+l^2)X=0. The operator D^2+l^2 is clearly linear. So if (D^2+l^2)f=0 and (D^2+l^2)g=0, then (D^2+l^2)(af+bg)=a(D^2+l^2)f+b(D^2+l^2)g=0.
 

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