Capacitance of a Sphere: A Quick Calculation Method

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Could anyone tell me the capacitance of a one food diameter metal sphere. I know that this is a one terminal component but it still should have a capacitance. If a charge of Q is small and a 6 inch radius is drawn about the point then that 6 inch radius ( 12 in diameter ) should have a voltage associated with it. C = Q/V

Thanks
 
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arydberg said:
Summary:: capacitance of a sphere

Could anyone tell me the capacitance of a one food diameter metal sphere. I know that this is a one terminal component but it still should have a capacitance. If a charge of Q is small and a 6 inch radius is drawn about the point then that 6 inch radius ( 12 in diameter ) should have a voltage associated with it. C = Q/V

Thanks
Look up the capacitance of a concentric spherical capacitor and then make the outer sphere radius infinitely large. To find a numerical answer, don't forget to convert the one food diameter to conventional SI units.
 
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It may be handy to know that in the Centimetre-Gram-Second (cgs) system of units, the capacitance of a sphere is equal to its radius, and the unit of capacitance is the centimetre. By good fortune, a centimetre of capacitance is approximately equal to a picofarad. 1cm = 1.11pF. So the capacitance of a sphere is approximately equal to its radius in centimetres.
 
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tech99 said:
It may be handy to know that in the Centimetre-Gram-Second (cgs) system of units, the capacitance of a sphere is equal to its radius, and the unit of capacitance is the centimetre. By good fortune, a centimetre of capacitance is approximately equal to a picofarad. 1cm = 1.11pF. So the capacitance of a sphere is approximately equal to its radius in centimetres.
Thank you
 
In SI units the capacitance is ##4\pi \epsilon_0R## or about ##R/(9\times 10^9)##. The result is the same as the one mentioned by tech99.
 
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arydberg said:
Summary:: capacitance of a sphere

Could anyone tell me the capacitance of a one food diameter metal sphere. I know that this is a one terminal component but it still should have a capacitance. If a charge of Q is small and a 6 inch radius is drawn about the point then that 6 inch radius ( 12 in diameter ) should have a voltage associated with it. C = Q/V

Thanks
Right, and it's a quick way to come up with the capacitance of the sphere:
V = kQ/a = Q/C, k = 9e9 SI.