Capacitance Question: Charge Change in Circuit

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SUMMARY

The discussion centers on analyzing the charge behavior of capacitors in a circuit after switches are closed. The key equations used include the equivalent capacitance formula (1/Ceq) = (1/c1) + (1/c2) and the charge formula q = cv. The participant initially calculated that the charge decreases in all examples, which was identified as incorrect. A request for clarification on the voltage across each capacitor before the switch closure was made, indicating a need for a detailed step-by-step solution for accurate analysis.

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Homework Statement



After the switches have been closed, in which circuit will the charge on the left hand capacitor increase? decrease? stay the same?

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[PLAIN]http://img714.imageshack.us/img714/3369/capacitance.png

Homework Equations



(1/Ceq) = (1/c1) + (1/c2)
q = cv

The Attempt at a Solution



Okay so, I figured if I solve the total voltage of each capacitor, and then use q=cv, using Ceq and the total voltage, then I would get my answer. However, my answers indicated that the charge decreases in every example, and this is supposedly the wrong answer. Can someone please help?
 
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Pick one of the figures and show your work. For example, for figure (ii), what is the voltage on each capacitor before the switch is closed?
 

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