C1= 2.0 μF
C2= 5.0 μF
the resistor has a resistance of 0.10 MΩ
The circuit shows the charging of a capacitor
a) At t=0 the switch is closed. What is the initial measuring on the ammeter?
b) After the current has decayed to zero what are the voltages at points A,B and C?
Q= Qo e^(-t/cr)
The Attempt at a Solution
Well at t= 0 the current should be 0
and then for the b) the current should decay to zero at t= ∞ , right? But if I use this idea I can't calculate any voltages and I just get confused.
At first I thought since the current decayed to zero... the capacitor were fully charged so . I found the effective capacitance
Q= 1.43x10^-6 x 3 = 4.29x10^-6C
Then I used that to find the voltage at each point.
But my teacher didn't agree...
Help is much appreciated!!