Capacitance question What is C_eq?

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SUMMARY

The discussion centers on calculating the equivalent capacitance (C_eq) of a series capacitor combination, specifically addressing the relationship between C_eq and individual capacitor values (C1, C2, C3, C4). The correct answer, according to the answer key, is that C_eq is less than C1, which is confirmed by applying the formula for capacitors in series: 1/C_eq = 1/C1 + 1/C2 + ... + 1/Cn. The confusion arises from miscalculating the reciprocal of the total capacitance, leading to incorrect interpretations of the values.

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  • Ability to perform reciprocal calculations accurately.
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Homework Statement


C2<C2<C3<C4 for the capacitor combination shown. What is C_eq?

a) less than C1
b) more than C4
c) between C2 & C3
d) less than C2
e) any value since it depends on the voltage applied

Homework Equations


Capacitors in series: 1/Ceq = 1/C1 + 1/C2 +... 1/Cn


The Attempt at a Solution


The answer key says (a) but I don't see how that works. I plugged in some numbers, for example with 4, 3, 2, 1 for the four capacitors and 5, 4, 3, 2 and for the former it's between C2 and C3 but for the latter it's greater than C4 so it seems like (e) would be the better answer.
 

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The capacitor C1 has the least capacitance and the capacitor C4 has the most. You are neglecting to take the reciprocal of your answer. Notice that the equation you're using is for 1/Ceq.
 

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