Calculate the equivalent capacitance in the network

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SUMMARY

The discussion focuses on calculating the equivalent capacitance of a network consisting of four capacitors: C1 = 8.55 μF, C2 = 4.00 μF, C3 = 8.65 μF, and C4 = 3.20 μF. The participant identifies that C1 and C2 are in series, while C3 and C4 are in parallel with the series combination of C1 and C2. The formula used for the equivalent capacitance is C = (C1 * C2) / (C1 + C2) + C3 + C4, which accurately reflects the configuration of the capacitors.

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  • Ability to perform calculations with microfarads (μF)
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Bishop556
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Homework Statement



Calculate the equivalence capacitance of the network; where C1 = 8.55 μF, C2 = 4.00μF ,
C3 = 8.65 μF, C4 = 3.20 μF


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Homework Equations



Capacitane in parallel: C = C1 + C2 + ... Cn
Capacitance in series: 1/C = 1/C1 + 1/C2 + .. 1/Cn

The Attempt at a Solution



I believe that C1 and C2 are in series and are parallel to C3. Also, C4 is parallel to C3, so the formula for the equivalence capacitance would be:

C = C1C2/(C1+C2) + C3 +C4
 
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Bishop556 said:
I believe that C1 and C2 are in series and are parallel to C3.
I see a circuit that involves C1 and nothing else.
 

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