In the circuit shown in the figure the voltage of the battery is 15.0 V, and the capacitors have the following capacitances: C1 = 2.32 mF, C2 = 2.25 mF, C3 = 4.85 mF, C4 = 4.89 mF
What is the equivalent capacitance of the four capacitors?
Two sets of series capacitors that are parallel to each other
Ceq=(1/C1+1/C2+1/C3...)^-1 ---- series
Ceq=(C1+C2+C3...) --- parallel
The Attempt at a Solution
=(7.17)(7.14) / 14.31
= 3.58 mF
According to online hw system, it's wrong. Is my equation incorrect?