Capacitor charge 195 μs after switch opens in RC circuit

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deerhunt713
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Three resistors and a capacitor are in a circuit with a battery:
R1 = 23 Ω
R2 = 13 Ω
R3 = 15 Ω
C = 6.2 µF
V = 17 V
The switch has been closed for a long time. What will the charge be on the capacitor 195 μs after the switch is opened?

picture
https://online-s.physics.uiuc.edu/cgi/courses/shell/common/showme.pl?courses/phys212/fall09/homework/06/11_paired/image.gif

 
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WHat are your thoughts on the matter? Is this a charging or discharging capacitor 195 μs after the switch is opened? What are the relevant equations to describe this?
 
ok well the capacitor is fully charged, so the voltage of the capacitor is the same as the battery, from there i can find the max charge. then i used the equation Qmax(1-e^(t/CR))
where i used 28 for the resistance. but that's not giving me the right answer
 
Try again. The voltage across the capacitor is the same as across the series combination R2+R3. That's not the voltage across the battery. What is it?
 
kuruman said:
Try again. The voltage across the capacitor is the same as across the series combination R2+R3. That's not the voltage across the battery. What is it?

That's not the only problem. The current through C is not the current through either R1 or R2+R3 so you can't use those in Qmax(1-e^(t/CR) either.

I recommend replacing V, R1, R2 and R3 with their Thevenin equivalent.