Capacitor Diagram Transormations

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The discussion focuses on understanding the transformation of a capacitor schematic, specifically how to derive the equivalent capacitance of 4.308pF from three 7pF capacitors. Participants note that the transformation involves converting a Y network to a Δ configuration, illustrated in provided figures. The conversation emphasizes the need for impedance transformation formulas, suggesting that these should have been covered in prior lectures. An exercise related to the schematic is also mentioned to reinforce the concepts discussed. Overall, the thread seeks clarity on the transformation process and its implications for equivalent capacitance calculations.
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I am having a difficult time understanding how they're transforming this capacitor schematic...what exactly is going on here? The example states that each cap is 7pF and the final answer C(eq) = 4.308pF...but why?
 

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There should be 3 figures to illustrate what the dialogue is describing, The first figure would be identical to that in your image #2. Then the Y network at its centre is transformed to Δ, producing the figure you have as image #1.

Finally, to consolidate the topic, they set you an exercise to apply what you have learnt, and this exercise is centred around your image #2.

You'll need the formulae for these impedance transformations, presumably your lectures have covered the topic? http://www.allaboutcircuits.com/vol_1/chpt_10/13.html
 
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