1. The problem statement, all variables and given/known data Capacitors of 7.6 µF and 2.1 µF are charged as a parallel combination across a 333V battery. The capacitors are disconnected from the battery and each other. They are then connected positive plate to negative plate and negative plate to positive plate. Find the resulting charge on the first capacitor. Answer in units of µC. 2. Relevant equations C = Q/V 3. The attempt at a solution I'll preface this by saying that I looked at other threads about this, but it's still just not working out for me so I think I need to actually converse about it. Knowing that parallel capacitors have the same voltage: q1 = (7.6e-6)(300V) = .00228C q2 = (2.1e-6)(300V) = 6.3e-4C Then: Qtotal = q1 + q2 = .00291C To check: Qtotal = CtotalV (7.6e-6C + 2.1e-6c)(300V) = .00291C It's just that from here, I don't know where to go at all. When the charges are connected one end to another, are they in a series or are they parallel? Hints aren't working very well for me. I don't know if that's because I'm behind in physics or what, but nothing that's being thrown against the wall is sticking.