1. The problem statement, all variables and given/known data Two capacitors, one that has a capacitance of 4.30 µF and one that has a capacitance of 12.1 µF, are connected in parallel. The parallel combination is then connected across the terminals of a 9.0-V battery. Next, they are carefully disconneted so that tehy are not discharged. They are then reconnected to each other--the positive plate of each capacitor connected to the negative plate of the other. Find the potential difference across each capacitor after they are reconnected. C1 = 4.30µF C2= 12.1µF V = 9v 2. Relevant equations C = Q/V 3. The attempt at a solution Before they are reconnected each capacitor is charged to the following: C1(V) = Q1 --> (4.3µF)(9v) = 38.7µC C2(v) = Q2 --> (12.1µF)(9v) =108.9µC But I lose my way after the reconnection. I understand that the voltage will change are charge will rearrange but when it comes to the specifics im not entirely sure. Any help would be appreciated.