Carnot engine efficiency and exhaust problem

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SUMMARY

The efficiency of a Carnot heat engine with an exhaust temperature of 121°C and an efficiency of 13.4% requires the intake temperature to be calculated using the formula e=1-(Tc/Th). The correct approach involves converting the exhaust temperature to Kelvin, resulting in an intake temperature of approximately 412.723 K, or 139.723°C. The initial calculation was incorrect due to the use of the Celsius scale instead of the absolute temperature scale.

PREREQUISITES
  • Understanding of Carnot heat engine principles
  • Knowledge of thermodynamic temperature scales, specifically Kelvin
  • Familiarity with efficiency calculations in thermodynamics
  • Ability to manipulate algebraic equations
NEXT STEPS
  • Study the principles of thermodynamics, focusing on the Carnot cycle
  • Learn about temperature conversions between Celsius and Kelvin
  • Explore the concept of thermal efficiency in heat engines
  • Practice solving problems involving Carnot engine efficiency
USEFUL FOR

Students studying thermodynamics, engineers working with heat engines, and anyone interested in understanding the efficiency of thermal systems.

lzh
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Homework Statement


The exhaust temperature of a Carnot heat engine is 121◦C. What is the intake temperature if the efficiency of the engine is 13.4 %? Answer in units of ◦C.


Homework Equations


e=1-(Tc/Th)


The Attempt at a Solution


This seems like just a plug and chug problem:
0.134=1-(121/Th)
Th=139.723 ◦C
However, this answer is wrong-according to my Quest web homework. Am I missing something here? Thanks
 
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Hi lzh,

lzh said:

Homework Statement


The exhaust temperature of a Carnot heat engine is 121◦C. What is the intake temperature if the efficiency of the engine is 13.4 %? Answer in units of ◦C.


Homework Equations


e=1-(Tc/Th)


The Attempt at a Solution


This seems like just a plug and chug problem:
0.134=1-(121/Th)
Th=139.723 ◦C
However, this answer is wrong-according to my Quest web homework. Am I missing something here? Thanks

The Celsius scale is not a thermodynamic temperature scale. You need to use a temperature scale such as Kelvin here.
 
Oh! I see! Thanks! I got it now!
 

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