Right i'm not stuck on the whole question it's just one bit i need advice on rather than answers. I have a cart with 2 wheels on a 30degree slope and it is in equilibrium, i know how to work out the forces directly down onto the slope mg*cos30 and the force pulling it down the slope mg*sin30. as its it equilibrium the opposing forces are the same. however where i am stuck is that a force is applied to the handle facing up the slope, i know this would be the same as the force pulling down the slope... BUT the handle is 1 metre lower than the line parallel to the incline which runs through the carts centre of gravity which gives the forces up and down the slope mg*sin30. how to i account for this lower handle to work out the force needed to be applied to it to hold the cart in equilibrium? any advice would be great as i feel i'm stuck on something so simple. Michael. The line through the centre of gravity is 2 metres above the slope if that makes a difference.