Casimir effect - Does it fit? Or NOT?

  • Context: Graduate 
  • Thread starter Thread starter eemaestro
  • Start date Start date
  • Tags Tags
    Casimir effect Fit
Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
3 replies · 3K views
eemaestro
Messages
6
Reaction score
0
I just heard about the Casimir effect:
http://en.wikipedia.org/wiki/Kashmir_effect

Is this for real? Or is it just speculation?
If it's real, then how in the name of science does it fit into the four fundamental forces?!
http://hyperphysics.phy-astr.gsu.edu/hbase/forces/funfor.html

I think it's just a fancy name for friction. I think friction is an example of electromagnetic force, same
as the pressure of standing on the floor. But I could be wrong! The pressure of standing on the floor could be a result of gravity! So which is it? EM or Gravity ? Or both?! We can't even talk about the Casimir effect (if it even exists) until we can clear up something as simple as standing on the floor. :!)
 
Last edited:
Physics news on Phys.org
Casimir effect is very real and there have been numerious experiments attesting the existence of that macroscopic force. That's not something new, it can be interesting, but it's a just a mere effect of EM field quantization in various geometries. As for the 4 forces, well they go hand in hand, since the theory of 4 forces is based on (gauge) field quantization which also explains the existence of the Casimir force.
 
Here is page by Ulf Leonhardt explaining how manipulating the Casimir effect may allow advances in the reduction of friction in nano-machines.

http://www.st-andrews.ac.uk/~ulf/levitation.html
 
Last edited by a moderator:
the wiki page must be in error, there is no way that this could be true:

Indeed at separations of 10 nm — about a hundred times the typical size of an atom — the Casimir effect produces the equivalent of 1 atmosphere of pressure (101.3 kPa)

1 atm over a separation as large as 100 angstoms? no way