Cauchy's differintegral formula

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The Cauchy's differintegral formula is expressed as \(\frac{d^n}{dz^n}f(z_0)=\frac{n!}{2\pi i!}\oint_{\gamma}\frac{f(z)}{(z-z_0)^{n+1}}dz\). This formula is valid when the derivative is taken with respect to \( \bar{z} \) as well, represented by \(\frac{d^n}{d\bar{z}^n}f(z_0)\). The discussion raises the question of the validity of the integral when computed with respect to \( \bar{z} \), prompting a request for proof. Participants express uncertainty regarding the proof of this concept.

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Jhenrique
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The Cauchy's differintegral formula is: [tex]\frac{d^n}{dz^n}f(z_0)=\frac{n!}{2\pi i!}\oint_{\gamma}\frac{f(z)}{(z-z_0)^{n+1}}dz[/tex] But this formula is valid if the derivative is wrt ##\bar{z}## ? [tex]\frac{d^n}{d\bar{z}^n}f(z_0)[/tex] And if the integral is wrt ##\bar{z}## is valid too? [tex]\frac{n!}{2\pi i!}\oint_{\gamma}\frac{f(z)}{(z-z_0)^{n+1}}d\bar{z}[/tex]
 
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Try to prove it!
 
micromass said:
Try to prove it!

I'm not capable to prove it!
 

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