- #1

squareroot

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- Homework Statement
- Two particles of equal mass (m = 1GeV/c^2) collide under an angle of 30 degrees. Their momenta are 200GeV/c and 100GeV/c. What is the energy in the center of mass? How many \pi^{0} can be formed in this collision?(m_{\pi0} = 135MeV/c^2)

- Relevant Equations
- p_{1} = (E_{1}, \vec{p_{1}})

p_{2} = (E_{2}, \vec{p_{2}})

in the Center of Mass frame one has : |\vec{p_{1}}| = |\vec{p_{2}}|; E_{1} = E_{2} = E

The center of mass energy is S = (E_{1} + E_{2})^2 - (\vec{p_1}+\vec{p_2}) = 4E^2

Starting from the center of mass energy S = (E_{1} + E_{2})^2 - (\vec{p_1}+\vec{p_2})

knowing that E^2 = m_{0}c^4 + p^2*c^2 one has

S = (E_{1} + E_{2})^2 - (\vec{p_1}+\vec{p_2}) = ( m_{0}c^4 + p_{1}^2*c^2) + m_{0}c^4 + p_{2}^2*c^2)^2 - p_{1}^2 - p_{2}^2 - 2p_{1}p_{2}cos \{theta}

and then subtituing for p_{1}, p_{2} and the angle. Could you please tell me if this approach is correct?

Thank you in advance,

sqt

knowing that E^2 = m_{0}c^4 + p^2*c^2 one has

S = (E_{1} + E_{2})^2 - (\vec{p_1}+\vec{p_2}) = ( m_{0}c^4 + p_{1}^2*c^2) + m_{0}c^4 + p_{2}^2*c^2)^2 - p_{1}^2 - p_{2}^2 - 2p_{1}p_{2}cos \{theta}

and then subtituing for p_{1}, p_{2} and the angle. Could you please tell me if this approach is correct?

Thank you in advance,

sqt