Center of Mass Frame for Elastic Collision

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Homework Help Overview

The problem involves two spheres of different masses colliding elastically on a frictionless surface. The objective is to determine their final velocities in the center of mass reference frame after a specified loss of kinetic energy during the collision.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the equations related to kinetic energy and momentum conservation, questioning how to apply them given the loss of kinetic energy. There are attempts to express the final velocities in terms of initial conditions and the equations provided.

Discussion Status

Some participants have provided equations and attempted to solve for the final velocities, while others seek clarification on the variables involved. There is ongoing exploration of the relationships between kinetic energy and momentum, with no explicit consensus reached yet.

Contextual Notes

Participants are working under the constraint of a 25% loss of total initial kinetic energy, which adds complexity to the problem. There is also mention of using specific software for calculations, indicating a reliance on computational tools in the discussion.

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Homework Statement


Two spheres of equal radius and masses 5.00 kg and 15.0 kg are sliding towards each other along the same straight line across a frictionless, horizontal surface. Vi1 = 15.0 m/s and Vi2= -9.00 m/s, respectively. During the collision, 25% of the total initial kinetic energy is lost...use the results above to find the final velocities of the two objects in the center of mass reference frame.


Homework Equations


Kf = 1/2 m1 v1f ^2 + 1/2 m2 v2f ^2
Kf = 1/2 M Vcm ^2 + 1/2 m1 u1f ^2 + 1/2 m2 u2f^2
m1 u1f + m2 u2f = 0


The Attempt at a Solution


This was a multi-step problem in which my professor gave us the above equations. I already solved for Vcm, which is -3.0 m/s. This would give sphere 1 a ui of -12.0 m/s and sphere 2 a ui of 12.0 m/s. I calculated Ki to be 1170 Joules, and calculated the value of Kf to be 75% of the value, or 877.5 Joules. However, I am unsure as to how to use the above equations in order to solve for uf and vf, since there is a change in kinetic energy. I tried several things, like plugging in random numbers, solving for one of the variables and plugging it back in, and have so far been stumped. Please help!
 
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you have these things:

Kf >> v1_f and v2_f
pf >> v1_f and v2_f

pf = pi
Kf = 0.75Ki
so two unknowns and two equations!

Hopefully this may help you
 
Last edited:
To what is pi and pf referring? Is that momentum? I'm afraid I'm still a bit lost.
 
YEs

$$0.5\,\left( 5\,{vI}^{2}+15\,{vF}^{2}\right) =877.5$$
$$5\,vI+15\,vF=-60$$
$$[[vI=-\frac{3\,\sqrt{105}+6}{2},vF=\frac{\sqrt{3}\,\sqrt{5}\,\sqrt{7}-6}{2}],[vI=\frac{3\,\sqrt{105}-6}{2},vF=-\frac{\sqrt{3}\,\sqrt{5}\,\sqrt{7}+6}{2}]]$$

oops, here are two equations and their solution using maxima
0.5*(5*vI^2+15*vF^2)=877.5;
5*vI+15*vF=-60
[[vI=-(3*sqrt(105)+6)/2,vF=(sqrt(3)*sqrt(5)*sqrt(7)-6)/2],[vI=(3*sqrt(105)-6)/2,vF=-(sqrt(3)*sqrt(5)*sqrt(7)+6)/2]]

Is that right answer?
 
rootX said:
$$0.5\,\left( 5\,{vI}^{2}+15\,{vF}^{2}\right) =877.5$$
$$5\,vI+15\,vF=-60$$
$$[[vI=-\frac{3\,\sqrt{105}+6}{2},vF=\frac{\sqrt{3}\,\sqrt{5}\,\sqrt{7}-6}{2}],[vI=\frac{3\,\sqrt{105}-6}{2},vF=-\frac{\sqrt{3}\,\sqrt{5}\,\sqrt{7}+6}{2}]]$$

For LaTex on the forum, use [ tex ]...[ /tex ] tags, without the spaces inside the square brackets, instead of $.
 
[tex]0.5\,\left( 5\,{vI}^{2}+15\,{vF}^{2}\right) =877.5[/tex]
[tex]5\,vI+15\,vF=-60[/tex]
[tex][[vI=-\frac{3\,\sqrt{105}+6}{2},vF=\frac{\sqrt{3}\,\sqrt {5}\,\sqrt{7}-6}{2}],[vI=\frac{3\,\sqrt{105}-6}{2},vF=-\frac{\sqrt{3}\,\sqrt{5}\,\sqrt{7}+6}{2}]][/tex]

Let's see
 
Thank you so much!

(My maxima makes it for me :D, but puts $$)
 
Wow, thank you for all of the help!
 

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