Center of Mass question (help)?

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SUMMARY

The discussion focuses on calculating the center of mass (CoM) of a human leg modeled as two uniform segments: the upper leg and the lower leg. For a 70.0 Kg individual, the upper leg mass is 8.60 Kg and the lower leg mass is 5.25 Kg. The correct method to find the x-coordinate of the CoM involves using the formula ∑ m*x/∑ m, where the CoM of each segment is located at its midpoint. The user initially miscalculated the CoM by incorrectly applying the formula.

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driftk
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I tried this problem but only managed to somewhat understand Part A. But that answer is wrong as well, so can someone guide me through steps of finding the answer: Thank you.

To keep the calculations fairly simple, but still reasonable, we shall model a human leg that is 0.92 m long (measured from the hip joint) by assuming that the upper leg and the lower leg (which includes the foot) have equal lengths and that each of them is uniform. For a 70.0 Kg person, the mass of the upper leg would be 8.60 Kg, while that of the lower leg (including the foot) would be 5.25 Kg.

A. Find the x-coordinate of the center of mass of this leg, relative to the hip joint, if it is stretched out horizontally.

- i got 0.35 as my answer but it was wrong. My method was this: (5.25*0.92)/ total mass of 13.85. What am I doing wrong?

B. Find the x-coordinate of the center of mass of this leg, relative to the hip joint, if it is bent at the knee to form a right angle with the upper leg remaining horizontal.
 
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driftk said:
I tried this problem but only managed to somewhat understand Part A. But that answer is wrong as well, so can someone guide me through steps of finding the answer: Thank you.

To keep the calculations fairly simple, but still reasonable, we shall model a human leg that is 0.92 m long (measured from the hip joint) by assuming that the upper leg and the lower leg (which includes the foot) have equal lengths and that each of them is uniform. For a 70.0 Kg person, the mass of the upper leg would be 8.60 Kg, while that of the lower leg (including the foot) would be 5.25 Kg.

A. Find the x-coordinate of the center of mass of this leg, relative to the hip joint, if it is stretched out horizontally.

- i got 0.35 as my answer but it was wrong. My method was this: (5.25*0.92)/ total mass of 13.85. What am I doing wrong?

B. Find the x-coordinate of the center of mass of this leg, relative to the hip joint, if it is bent at the knee to form a right angle with the upper leg remaining horizontal.

The Center of Mass is the ∑ m*x/ ∑ m

What they want you to do is calculate the CoM using both the two leg parts, upper and lower. Since they say that each piece is uniform, then you can assume that the CoM's of each piece are located half way on each part.
 

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