Center of Pressure: 2b/3 from Free Surface

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SUMMARY

The center of pressure (COP) for a completely submerged vertical plate is located at a depth of 2b/3 from the free surface when the top edge of the plate is at the water surface. As the plate sinks, the center of pressure shifts towards the centroid of the plate, reaching b/2 when fully submerged. The calculations provided confirm that the center of pressure is accurately determined using the formula yp = s + b/2 + b²/(12(s+b/2)), resulting in a depth of 8.61m for a plate with a height of b = 1.2m and s = 8m.

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Homework Statement


can someone explain about the Fr acting at a distance 2b/3 from free surface firectly beneath the centroid of the surface ?

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The Attempt at a Solution


does the author mean the center if pressure ( point where the FR acts) of the completely submerged plate (90 degree) is at 2b/3 from the top of the surface ? p/s : the whole vertical length of the submerged surface is b
 

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foo9008 said:
does the author mean the center if pressure ( point where the FR acts) of the completely submerged plate (90 degree) is at 2b/3 from the top of the surface ? p/s : the whole vertical length of the submerged surface is b

Yes. When the top edge of the plate is at the surface Fr acts at a depth of 2b/3. If the plate sinks further Fr moves towards the centre of the plate (eg towards b/2).

See "2. COP Fully submerged plate"...

http://people.exeter.ac.uk/TWDavies...tic Force on a submerged vertical surface.htm
 
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CWatters said:
Yes. When the top edge of the plate is at the surface Fr acts at a depth of 2b/3. If the plate sinks further Fr moves towards the centre of the plate (eg towards b/2).

See "2. COP Fully submerged plate"...

http://people.exeter.ac.uk/TWDavies/solid mechanics/Hydrostatic Force on a submerged vertical surface.htm
can you explain why in this case , the center of pressure not at 2/3 of the submerged plane ? if it's 2/3 , it should be 8= (1.2/3) = 8.8 m , right ? why the working only showed 8.61m?
 

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It's only at 2/3rds of the height of the plate when the top edge of the plate is at the surface. In the case of the car the top edge is 8m down.

I get the same answer using the equation in your notes...

yp = s + b/2 + b2/(12(s+b/2)
= 8 + 1.2/2 + 1.22/(12(8+b/2)
= 8 + 0.6 + 0.014
= 8.61m

and the equation at the link I posted..

= 2/3 * (y23 - y13)/(y22 - y12)
= 2/3 * (9.23 - 83)/(9.22 - 82)
= 2/3 * (778.69 - 512)/ (84.64 - 64)
= 2/3 * 266.69/20.64
= 8.61m
 
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CWatters said:
the plate is at the s
CWatters said:
It's only at 2/3rds of the height of the plate when the top edge of the plate is at the surface. In the case of the car the top edge is 8m down.

I get the same answer using the equation in your notes...

yp = s + b/2 + b2/(12(s+b/2)
= 8 + 1.2/2 + 1.22/(12(8+b/2)
= 8 + 0.6 + 0.014
= 8.61m

and the equation at the link I posted..

= 2/3 * (y23 - y13)/(y22 - y12)
= 2/3 * (9.23 - 83)/(9.22 - 82)
= 2/3 * (778.69 - 512)/ (84.64 - 64)
= 2/3 * 266.69/20.64
= 8.61m
so, when the top edges of the submerged object is located exactly at the water surface(s=0) , then the center of pressure of submerged object will be at exactly 2/3 of the height of the submerged object ?
 
Yes. That's mentioned in your image dsc_0525-jpg.
 
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