Centre of mass of velocity (q61)

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SUMMARY

The discussion focuses on calculating the center of mass of velocity for two masses, m1 and m2, moving at velocities v1 and v2, respectively. The formula used is the center of mass of velocity = (m1*v1 + m2*v2) / (m1 + m2). Participants clarify that if both masses move at the same speed, the center of mass will also move at that speed, but variations in individual speeds will affect the overall speed of the center of mass. This understanding is crucial for solving related physics problems.

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  • Understanding of basic physics concepts, particularly mass and velocity.
  • Familiarity with the formula for center of mass in a two-body system.
  • Knowledge of how mass distribution affects motion.
  • Basic algebra skills for manipulating equations.
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  • Study the implications of mass distribution on the center of mass in multi-body systems.
  • Learn about the conservation of momentum in relation to center of mass calculations.
  • Explore examples of center of mass in different physical scenarios, such as collisions.
  • Investigate the role of center of mass in rotational dynamics.
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jack1234
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Hi, for the following problem
http://tinyurl.com/249gz8
the answer is d

What i have done is
Centre of mass of velocity
=(m1*v1+m2*v2)/(m1+m2)

but I am not sure how does it leads to the result d...
can anybody help on this?
 
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It might be easier to view this conceptually. What if both masses had a speed of v1? Then the speed of the center of mass would be v1, right? But some of the total mass (m2) is moving faster, so what must happen to the speed of the center of mass?

And it works the other way as well. What if both masses had a speed of v2. Then the speed of the center of mass would be v2? But some of the total mass (m1) is moving slower, so what must happen to the speed of the center of mass?
 
I see, thanks for the help :)
 

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