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Centripetal force exerted on Earth

  1. Feb 21, 2010 #1
    Here is the problem and the choices:
    Calculate the centripetal force exerted on
    the Earth by the Sun. Assume that the period
    of revolution for the Earth is 365.25 days,
    the average distance is 1.5 × 10^8 km and the
    Earth’s mass is 6 × 10^24 kg.
    The choices are:
    1. 3.56775 × 10^22 N
    2. 2.66331 × 10^32 N
    3. 7.24562 × 10^22 N
    4. 1.62932 × 10^21 N
    5. None of these
    6. 3.56775 × 10^19 N
    7. 4.6238 × 10^29 N
    8. 1.28439 × 10^26 N
    9. 7.24562 × 10^20 N
    __________________________________________________
    Here is the attempted solution ( got choice # 6 but it is not correct)

    2πr=D
    (2)(π)(1.5 * 10^8) = 942477796.1 m=D

    D = VT
    V = D/T
    V = (942477796.1) / ( 365.25 * 24 * 60 * 60)
    V = 29.86 m/s


    F = MV^2 / R
    F = (6 * 10^24)(29.86)^2 / (1.5 * 10^8)
    F = 3.56775 * 10^19
     
  2. jcsd
  3. Feb 21, 2010 #2

    PhanthomJay

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    Science Advisor
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    Gold Member

    that ditance is in km, not m
    looks like your off by a factor of 1000. Simple units error.
     
  4. Feb 21, 2010 #3
    wow..thanks for catching my mistake!!
     
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