An experiment is conducted on a "strange" planet to determine the acceleration due to the force of gravity there. A 2 meter length pendulum is suspended and put into horizontal circular path. Data collected: the pendulum makes 10 revolutions in 25 seconds while sweeping out a circle of radius R=.209 meters.
Find "g" for this planet.
F = MA
Centripetal acceleration = V^2/R
The Attempt at a Solution
V = 10(2πR)/25 = .53m/s
R = .209
X eq: TCos60 = m(V^2)/R
Y eq: TSin60 = mg (no acceleration in the y direction)