- #1

demode

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**1. A dog sits 1.50 meters from the center of a merry-go-round with an angular speed of 1.20 rad/s. If the magnitude of the force that maintains the dog's circular motion is 40.0 N, what is the dog's mass?**

**2. Fc = (mv^2) / r**

**3. We were provided with the answer "18.5" but I do NOT understand how you can get this value using the aforementioned equation. I'll demonstrate what I did:**

40 * 1.50 = (1.20^2)m

60 = 1.44m

m = 41.6 kg

can someone explain to me what I'm doing wrong?

40 * 1.50 = (1.20^2)m

60 = 1.44m

m = 41.6 kg

can someone explain to me what I'm doing wrong?

**1. An olympic runner leaps over a hurdle. If the runner's initial vertical speed is 2.2 m/s, how much will the runner's center of mass be raised during the jump?**

**2. NO IDEA**

**3. Don't even know WHERE to begin. Can someone help me out?**