Circular Motion Question searching for Centripetal force

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SUMMARY

The discussion focuses on calculating the centripetal force for a 50 g weight swung in a circular motion with a radius of 90 cm at a speed of 5.9 m/s. The correct centripetal force is determined to be 1.9 N. The participant initially misapplied the tension formula, leading to an incorrect calculation of -3.9 N. The confusion arises from the dual use of the variable 'T' for both tension and period, necessitating clarification on vector addition of forces acting in different directions.

PREREQUISITES
  • Understanding of centripetal force and its formula: Fc = mv^2/r
  • Knowledge of vector addition in physics
  • Familiarity with tension in circular motion
  • Basic grasp of units of mass and force (grams to kilograms, Newtons)
NEXT STEPS
  • Review the concept of centripetal acceleration and its relationship to centripetal force
  • Study vector addition techniques for forces acting in different directions
  • Learn about the role of tension in circular motion and how it differs from period
  • Explore practical applications of centripetal force in real-world scenarios
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Students studying physics, particularly those focusing on mechanics, as well as educators seeking to clarify concepts of circular motion and force calculations.

claytonwideman
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Homework Statement


A 50 g weight is swung in a circle on the end of a 90 cm long string at the speed of 5.9 m/s, what is centripetal force? [1.9 N]

Homework Equations


Vc = (2πr)\T

|a| = v^2/r

Fc = T-Fg (not sure if T is force of tension or period, my teacher,incorrectly,uses it as both)

The Attempt at a Solution


Fc = T-Fg

T=2πr/v = .95845199...

Fc = T- Fg = -3.946

-3.9 ≠ 1.9 ∴ incorrect
 
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claytonwideman said:
Fc = T-Fg
What directions are T and Fg in? How do you add and subtract forces that act in different directions?
 

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