I'm having trouble coming up with a strategy for this problem. Any help is appreciated! "You are swinging a bucket (mass 1.00 kg) containing 2.00 kg of water at a constant angular speed in a vertical circular path (the path lies in a vertical plane) of radius 1.00 m. a.) What is the minimum angular speed that the bucket must have in order that the water does not fall out of the bucket at the top of its path? b.) Assuming that you are swinging the bucket at the angular speed found in (a), what is the force on your hand due to the bucket handle (give magnitude and direction) at i.) its highest point and ii.) its lowest point?" A Okay, so, first let me see if I understand correctly why the water does not fall out of the bucket at the top of the path at a certain speed... At the top of the circular path, there is a downward force of the object's weight and a downward force of my hand on the bucket. If I swing the bucket with enough force so that the magnitude of the acceleration of the bucket toward the center of rotation is greater than the magnitude of the acceleration due to gravity, the water cannot fall out because it is not accelerating as quickly as the bucket? Then if the acceleration of the bucket is faster than the acceleration of the water, the water will not fall out. Which means what I'm looking for is the speed of the bucket so that it is accelerating just fast enough so that any slower and its acceleration would be less than the acceleration of water. Does that mean I'm looking for when the acceleration of the bucket is equal to the acceleration of the water? If so I am not certain how to express this mathematically? B Really lost with this one... to increase the acceleration of the bucket I need to increase the force of my hand on the bucket. Does this mean the magnitude of the force of the bucket on my hand also increases? Again, I'm confused about how to express this mathematically. Thanks ahead of time for any insight.