- #1
PhysicsVA
- 1
- 0
Homework Statement
A 1.2 g pebble is stuck in a tread of a .76-m-diameter automobile tire, held in place by static friction that can be at most 3.6 N. The car starts from rest and gradually accelerates on a straight road. How fast is the car moving when the pebble flies out of the tire tread?
Homework Equations
net F= (mv^2)/r
t=I*α
v=ω*r
The Attempt at a Solution
I am self-studying physics right now and encountered this puzzling problem. Because it was in the rolling motions, I immediately tried to solve it using torque. Unfortunately this didn't result in anything, due to absence of distance or time. The only rotational force that dealt with velocity was centripetal, so I considered the force as centripetal force. Using the equation F=mv^2/r, I had (3.6N)=(.012kg)(v^2)/.38m
And finally, v=sqrt((.38m*3.6N)/.012kg)=10.677 m/s...
The textbook says this is wrong. Thus, my question is two-tiered: first, what did I do wrong? second, it looks like this is centripetal force, but why? (Isn't centripetal force inward, thus making friction face outward?)