Can a Charged Particle's Circular Trajectory Be Proven with Newton's Second Law?

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Homework Help Overview

The discussion revolves around proving that a charged particle's trajectory is circular when subjected to a magnetic field, specifically using Newton's Second Law and the magnetic force equation. The context is rooted in electromagnetism and classical mechanics.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants explore the relationship between the electromagnetic force and the particle's motion, questioning how the direction of the force influences the trajectory. There is also mention of a more complex scenario involving an initial velocity at an angle to the magnetic field.

Discussion Status

The discussion is ongoing, with participants raising questions about the implications of the magnetic force direction and its effect on the particle's path. Some guidance has been offered regarding the basic principles involved, but no consensus has been reached on the proof itself.

Contextual Notes

There is a hint of sarcasm in the discussion regarding the complexity of related problems, which may indicate varying levels of confidence among participants about tackling the original question.

SoberSteve2121
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For a charged particle the Velocity Vector is in the i direction and the magnetic field is in the -k direction, prove using Newton's Second Law that the trajectory of this charged particle must be circular. (Hint F=q(V x B) this is the magnetic Force equation.)
 
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I suspect that this belongs to the homework help zone.

How hard is that? Think of the direction of the electromagnetic force with respect to the particle's motion.
 
kuenmao said:
I suspect that this belongs to the homework help zone.

How hard is that? Think of the direction of the electromagnetic force with respect to the particle's motion.

Don't tell him that there's an even more "difficult" problem where the charge particle has an initial velocity at an arbitrary angle to the magnetic field. I'm sure we can't solve it to get the helical path that the charge particle makes.

:)

Zz.
 
I'm not sure the OP will get the sarcasm in that second statement, so...
 

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