Change in Linear Momentum with mass and velocity

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SUMMARY

The discussion focuses on calculating the change in kinetic energy and linear momentum of a 2700 kg truck that accelerates from 37 km/h to 47 km/h while turning. The change in kinetic energy is determined to be approximately 88450 J. For the change in linear momentum, the correct approach involves vector addition rather than simple subtraction of initial and final momentum values. The direction of the change in linear momentum requires the application of trigonometric functions to resolve the vector components.

PREREQUISITES
  • Understanding of linear momentum (p = m * v)
  • Basic knowledge of kinetic energy calculations
  • Familiarity with vector addition and trigonometric functions
  • Ability to convert units (e.g., km/h to m/s)
NEXT STEPS
  • Study vector addition in physics to understand momentum changes
  • Learn about kinetic energy formulas and their applications
  • Explore trigonometric functions for resolving vectors
  • Practice problems involving momentum changes in two dimensions
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Students studying physics, particularly those focusing on mechanics and momentum, as well as educators seeking to clarify concepts related to kinetic energy and vector analysis.

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Homework Statement




A 2700 kg truck traveling north at 37 km/h turns east and accelerates to 47 km/h.

(a) What is the change in the truck's kinetic energy?

(b) What is the magnitude of the change in the linear momentum of the truck?

(c) What is the direction of the change in the linear momentum of the truck?
__° (measured clockwise from east)

Homework Equations



p = m * v

The Attempt at a Solution


Part A is easy enough, i found it to be around 88450 J.

Part B, finding the change in momentum, I tried (m * v) - (M * V), with the latter part being the final speed (after converting to m/s), and got an answer of 7400 kg*m/s, which was wrong. I don't see why this doesn't work, so any explanation would be much appreciated.

Part C, I have no clue.. I don't remember seeing any formulas with angles in them.. after searching google i found some confusing looking formulas that have to do with angular momentum, but the problem specifically says linear.. so any insights on that would be appreciated as well, thanks.
 
Physics news on Phys.org
You're messing this up because momentum is a vector! Find the magnitudes of the initial and final momentum -- but then don't just subtract! Make a diagram and do the vector math (it will involve trig functions).
 

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