Change in momentum and force magnitude for a car accelerating over 66 seconds

[badboyben03]

The velocity of a 620-kg auto is changed from +11.0 m/s to +48.0 m/s in 66.0 s by an applied, constant force.

What change in momentum does the force produce?
What is the magnitude of the force?

 

[himanshu121]

Look up for the formulae and show what u come after if there is any doubt quote it

 

[M98Ranger]

The change in momentum produced by the force can be calculated using the formula Δp = mΔv, where Δp is the change in momentum, m is the mass of the auto, and Δv is the change in velocity. In this case, the change in momentum would be Δp = (620 kg)(48.0 m/s - 11.0 m/s) = 27,940 kg*m/s. This means that the force applied to the auto produces a change in momentum of 27,940 kg*m/s.

To calculate the magnitude of the force, we can use the formula F = Δp/Δt, where F is the force, Δp is the change in momentum, and Δt is the time it takes for the change in momentum to occur. In this case, the force would be F = (27,940 kg*m/s)/(66.0 s) = 423.03 N. Therefore, the magnitude of the force applied to the auto is 423.03 N.