1. The problem statement, all variables and given/known data A 178.0g ball is dropped from a height of 2.99m, bounces on a hard floor, and rebounds to a height of 1.36m. The impulse received from the floor is shown below. (Is a picture of a graph, Y-axis is force, X-axis is time. No numbers are labelled and is simply a line starting at 0 and goes to a peak and back down to zero like a triangle) What maximum force does the floor exert on the ball if it is exerted for 2.00ms 2. Relevant equations Impulse = Change in Momentum Momentum = mv Ui = mgy KE = 1/2 mv^2 3. The attempt at a solution Ui = mgy =5.2157 1/2 mv^2 = 5.2157 v=7.655m/s (to find velocity just as ball hits the ground) Pi = (0.178)(7.655) =1.3626 (Initial Momentum) Finding velocity just as it bounces back from floor Uf = KEi v=5.1629m/s Pf = 0.919 (final momentum) Change in momentum = 0.433 DeltaP(change in momentum) = 1/2 Fmax (0.002) Fmax = 443N (not correct answer) where did I go wrong?