Change in potential and kinetic energy for F=(-Ax+Bx²)i

[Xamfy19]

i need help for this problem.

A single conservative force acting on a particle varies as:

F=(-Ax+Bx^2)iN

where A=48N/m and B=93N/m^2 and x is in meters.
Find the change in potential energy as the particle moves from x0=3.2m to x1=2.8m. Answer in units of J.
Find the change in kinetic energy of the particle between the same two points. Answer in units of J.

I tried this problem and I thought it was zero. However, the answer is not zero. I also thought the kinetic energy was -277.696. Can anybody verify this answer? Thanks.

 

[jamesrc]

Try this:
$$\Delta U = -\int_{x_o}^{x_f} F(x)\cdot dx$$

 

[Xamfy19]

Thanks a lot

It worked. Thanks.

 

[Mac13]

cool thanks :)