- #1

zohaibtarar

- 2

- 0

## Homework Statement

A particle with a charge of 2e moves between two points which have a potential difference of 75V. What is the change in potential energy of the particle?

## Homework Equations

U = (75 V)(2e)

## The Attempt at a Solution

[/B]

When a particle with charge e moves through a potential difference of 1 volt, the change in potential energy is 1 eV. If the charge is some multiple of e—say Ne—the change in potential energy in electron volts is N times the potential difference in volts. Note: 1 eV = 1.602 x 10⁻¹⁹ J.

Potential is potential energy per unit charge. We define the potential V at any point in an electric field as the potential energy U per unit charge associated with a test charge q₀ at that point:

V = U/q₀

U = Vq₀

U = (75 V)(2e)

U = 150 eV

U = 150(1.602 x 10⁻¹⁹ J)

U = 2.403×10⁻¹⁷ J Solution: U = 150 eV = 2.403×10⁻¹⁷ Jjust need to make sure if i did this correctly? or do i need todo anything else?

Thank you