Change in Potential energy equals change in Kinetic energy?

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Homework Help Overview

The discussion revolves around the relationship between changes in potential energy and kinetic energy, particularly in the context of a block being pushed up an incline at constant velocity. Participants are exploring whether the equation W = ΔKE = -ΔPE holds true in this scenario, especially when the net work done is zero.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants examine the implications of constant velocity on net force and work done, questioning how potential energy changes while kinetic energy remains constant. They discuss the conditions under which the relationship between work, kinetic energy, and potential energy applies.

Discussion Status

Some participants have provided insights into the conditions necessary for the equation W = ΔKE = -ΔPE to be valid, noting that it applies only when total mechanical energy is conserved. Others have introduced the concept of non-conservative forces and how they affect the relationship between kinetic and potential energy.

Contextual Notes

There is an ongoing exploration of the definitions of work done by conservative versus non-conservative forces, and how these relate to changes in energy within the system. The discussion also highlights the importance of understanding the role of external forces in energy changes.

EMdrive

Homework Statement


I'm trying to digest the concept of change in potential energy being set equal to a change in kinetic energy. Does this relationship always hold? Please see below for more details.

Homework Equations



PE = mgh
KE = .5mv^2
W = ΔKE = -ΔPE
W = f*d

The Attempt at a Solution


[/B]
Lets say I have a block that is being pushed up an incline at constant velocity by a force F for a distance d. Because the velocity is constant, it follows that the net force on the object is 0, and therefore the total work done on the object should also be 0. This is further explained by the W = ΔKE equation in which the final and initial kinetic energies are the same, resulting in a work of 0 J. However, what baffles me is that while kinetic energy is clearly not changing, the potential energy is (height of the object is increasing). So the relationship W = ΔKE = -ΔPE does not hold because change in potential energy is some non-zero value... Can someone explain?
 
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EMdrive said:

Homework Statement


I'm trying to digest the concept of change in potential energy being set equal to a change in kinetic energy. Does this relationship always hold? Please see below for more details.

Homework Equations



PE = mgh
KE = .5mv^2
W = ΔKE = -ΔPE
W = f*d

The Attempt at a Solution


[/B]
Lets say I have a block that is being pushed up an incline at constant velocity by a force F for a distance d. Because the velocity is constant, it follows that the net force on the object is 0, and therefore the total work done on the object should also be 0. This is further explained by the W = ΔKE equation in which the final and initial kinetic energies are the same, resulting in a work of 0 J. However, what baffles me is that while kinetic energy is clearly not changing, the potential energy is (height of the object is increasing). So the relationship W = ΔKE = -ΔPE does not hold because change in potential energy is some non-zero value... Can someone explain?

Net work done is zero .Work done by gravity is non zero . PE is negative of work done by gravity .Hence PE is non zero .

Total mechanical energy is not conserved in this case .
 
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I see, that explains it. So the equation W = ΔKE = -ΔPE only applies in situations where total mechanical energy is conserved, which is not the case here (mechanical energy should be increasing here, correct?). But, just trying to understand, work can be 0 and the total mechanical energy of the system can still increase?
 
I just noticed it is your first post .

Welcome to PF !

EMdrive said:
I see, that explains it. So the equation W = ΔKE = -ΔPE only applies in situations where total mechanical energy is conserved, which is not the case here (mechanical energy should be increasing here, correct?). But, just trying to understand, work can be 0 and the total mechanical energy of the system can still increase?

W = ΔKE is Work Kinetic Energy theorem .W is net work done on the particle .This can further be written as Wnc + Wc =ΔKE . Wnc is work done by non conservative forces ( in your example it is work done by external agent pushing the block up .Wc is work done by conservative force ( in your example it is work done by gravity ) .

Now if you write Wc as -∆PE , Work KE theorem can be rewritten as ∆KE+∆PE = Wnc . This is the complete relation .It also applies in your case .In your example ,since Wnc ≠0 , ∆KE+∆PE ≠ 0 .

In your example net work done W = 0 . ∆KE+∆PE = Work done by external agent (whosoever is pushing the block up )

∆KE+∆PE = 0 only when conservative forces are acting .Here the force exerted by agent pushing the block up is a non conservative force .

Hence correct relation to use in your example is ∆KE+∆PE = Wnc .
 
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As @conscience explained, ∆KE= -∆PE for systems in which the following is true:

(1) no external work is done on the system (e.g., system is "isoloated")

(2) internal work is done by conservative forces only (like gravity or springs).

For a modern video on this concept using fancy, mind-blowing graphics, see
 
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conscience said:
I just noticed it is your first post .

Welcome to PF !
W = ΔKE is Work Kinetic Energy theorem .W is net work done on the particle .This can further be written as Wnc + Wc =ΔKE . Wnc is work done by non conservative forces ( in your example it is work done by external agent pushing the block up .Wc is work done by conservative force ( in your example it is work done by gravity ) .

Now if you write Wc as -∆PE , Work KE theorem can be rewritten as ∆KE+∆PE = Wnc . This is the complete relation .It also applies in your case .In your example ,since Wnc ≠0 , ∆KE+∆PE ≠ 0 .

In your example net work done W = 0 . ∆KE+∆PE = Work done by external agent (whosoever is pushing the block up )

∆KE+∆PE = 0 only when conservative forces are acting .Here the force exerted by agent pushing the block up is a non conservative force .

Hence correct relation to use in your example is ∆KE+∆PE = Wnc .
Thank you so much for the concise and complete explanation. It finally makes sense now! I really appreciate the help :)
 

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