Change in thermal energy and Temperature problem

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SUMMARY

The discussion focuses on calculating the change in internal energy (ΔU) and final temperature (Tf) for 1 mole of an ideal diatomic gas undergoing adiabatic compression to 89.700% of its initial volume. The initial conditions are set at 22.500°C and 16.100 L. The participant correctly applies the adiabatic process assumption, using the equation ΔU = W, and calculates work (W) as 267.175 J. However, the final temperature calculation yields an incorrect result, indicating a need for further verification of the equations used, particularly in relation to adiabatic processes.

PREREQUISITES
  • Understanding of ideal gas laws and properties
  • Familiarity with adiabatic processes in thermodynamics
  • Knowledge of internal energy equations for diatomic gases
  • Proficiency in logarithmic calculations and temperature conversions
NEXT STEPS
  • Review the derivation of the adiabatic process equations for ideal gases
  • Study the implications of vibrational degrees of freedom on internal energy
  • Learn about the relationship between work and internal energy in thermodynamic processes
  • Explore the use of the ideal gas law in calculating changes in state variables
USEFUL FOR

Students studying thermodynamics, particularly those focusing on gas laws and adiabatic processes, as well as educators seeking to clarify concepts related to internal energy and temperature changes in ideal gases.

laser123
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Homework Statement


Compute the change in internal energy, ΔU, and the final temperature, Tf, when 1 mole of an ideal, diatomic gas is compressed adiabatically to 89.700% of its initial volume. The starting point is 22.500°C and 16.100 L. (Assume that the vibrational degree of freedom stays inactive during the process.)

Homework Equations


eq. 1. W=NkTln(Vi/Vf)

eq. 2. Δu=Q+W

eq. 3. u=(f/2)NkT

The Attempt at a Solution



Okay since it's adiabatic I made the assumption Δu=w. So i used the abouve equation and solved for w=(6.02)(1.381)ln(16.1/14.447)=267.175 J

So i manipulate eq 3 and get u=(f/2)Nk(Tf-Ti) and (2u)/fNk+Ti=Tf=12.8548+295.65=308.505K. This the computer says is wrong?

Because when i find the change in Temp i plan on using du=(f/2)NkdT for the change in thermal energy
 
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laser123 said:
eq. 1. W=NkTln(Vi/Vf)
Does this equation hold for an adiabatic process?

when i find the change in Temp i plan on using du=(f/2)NkdT for the change in thermal energy

Sounds good.
 

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