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Change in wavelength, photon hits a free electron.

  1. Jul 20, 2012 #1
    1. The problem statement, all variables and given/known data
    A photon with initial momentum p collides with a free electron having
    a mass m that is initially at rest. If the electron and photon recoil in opposite
    directions, what will be the change in the photon’ wavelength? (Hint: use
    relativistic forms for energy and momentum.)

    2. Relevant equations
    Conservation of Energy:
    [itex]hf_{i}+m_{e}c^{2}=hf_{f}+\sqrt{p_{e}^{2}c^{2}+m_{e}^{2}c^{4}}[/itex]

    Conservation of Momentum:
    [itex]\boldsymbol{p_{i}}=\boldsymbol{p_{f}}+\boldsymbol{p_{e}}[/itex]

    3. The attempt at a solution
    I won't go through the whole derivation as it's quite a bit of latex but:
    If you square both equations above and introduce hf into the conservation of momentum equation, you can equate the two equations and rearrange. This will give you the compton scattering equation:

    [itex]\lambda_{2}-\lambda_{1}=\frac{h}{m_{e}c}(1-cos\theta)[/itex]

    If the recoiling electron and photon are to be in opposite directions this is an angle of 180°.
    Plugging this into the compton scattering equation gives:

    [itex]Δ\lambda=\frac{2h}{m_{e}c}[/itex]

    ,which is the change in wavelength.

    Does this look ok? As always everyone, thanks for the help!
     
  2. jcsd
  3. Jul 20, 2012 #2

    TSny

    User Avatar
    Homework Helper
    Gold Member

    Looks ok. But it seems to me that the intent of the problem was to set up the conservation equations for the specific case of 180 degree recoil. That makes the messy algebra simpler than the general case.

    However, if you can go through the algebra for the general case and then substitute the specific value of theta at the end, then that should certainly count as a solution!
     
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