Characteristic function and preimage?

Click For Summary

Homework Help Overview

The discussion revolves around the characteristic function of a subset S of the real numbers ℝ and its preimages with respect to the sets of rational numbers and positive real numbers. Participants are exploring the definitions and implications of the characteristic function, particularly in relation to the preimage of different sets.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to understand how to determine the preimages of the characteristic function for the sets of rational numbers and positive reals. Some participants suggest reviewing definitions to clarify the function's behavior.

Discussion Status

Participants are engaged in clarifying the definitions related to the characteristic function and its implications. There is a recognition of the need to understand the preimage concept better, with some guidance provided regarding the values of the characteristic function.

Contextual Notes

There is an indication that the original poster may be struggling with the foundational definitions of the characteristic function and its preimages, which could affect their understanding of the problem.

SMA_01
Messages
215
Reaction score
0
Characteristic function and preimage?

Homework Statement



Let S be a nonempty subset of ℝ.

Define χs= { 1 if x is in S and 0 if x is not in S

Determine χs-1(Q) [where Q=set of all rational numbers]

and χs-1((0,∞))

We haven't really dealt much with this function, and I really don't know how to go about doing this. I'm guessing for Q it will be all x in S such that f(x)=Q? Is that right?

Any help is appreciated,

Thanks.
 
Physics news on Phys.org


Then go back an review the definitions! Once you know the definitions, this problem is trivial.

Your function, "[itex]X_S[/itex]" (strictly speaking, "[itex]\chi_s[/itex]", the Greek letter "chi") is defined to be 1 if x is in S, 0 if not. In other words, the only possible value of x is 0 or 1, both of which are rational numbers, but only 1 is in [itex](0, \infty)[/itex].
 


Thank you, so for the rationals, the preimage of chi sub s is the set of all numbers in S and the complement of S, i.e. the set of all reals. Is that correct?
 


SMA_01 said:
Thank you, so for the rationals, the preimage of chi sub s is the set of all numbers in S [STRIKE]and[/STRIKE] or in the complement of S, i.e. the set of all reals. Is that correct?

Yes.

(There are no numbers which are both in set S and in the compliment of set S.)
 

Similar threads

  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 26 ·
Replies
26
Views
5K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
1
Views
2K
Replies
5
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K
Replies
20
Views
5K