Characters of Normal Subgroup of Index 2

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Discussion Overview

The discussion revolves around the properties of characters of a normal subgroup of index 2 within a finite group. Participants explore the implications of a character being zero on the quotient group and the relationships between irreducible characters of the subgroup and the group itself. The focus is on understanding the behavior of characters when restricted to conjugacy classes.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Homework-related

Main Points Raised

  • One participant notes that for a normal subgroup N of a finite group H with index 2, a character Chi belonging to Irr(H) is zero on H\N and can be expressed as Chi restricted to N = Theta 1 + Theta 2, where Theta 1 and Theta 2 are distinct irreducible characters of N.
  • Another participant suggests considering the induced character Ind_N^H(theta_1) and applies Frobenius Reciprocity to relate inner products of characters.
  • There is a question regarding the linearity of the inner product in the context of irreducible characters and whether can be separated into individual inner products.
  • A later reply emphasizes the orthonormality of irreducible characters and suggests looking into the construction of the induced character to reach the desired result.

Areas of Agreement / Disagreement

Participants express differing levels of familiarity with the material, but there is no explicit consensus on the final steps needed to show that Theta 1(n) = Theta 2(n) for n in the conjugacy class K. The discussion remains unresolved regarding the specific approach to take next.

Contextual Notes

Some assumptions about the properties of irreducible characters and their inner products may be implicit in the discussion. The notation and mathematical steps may also depend on the participants' familiarity with character theory and group representations.

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Hi There,

Ok, I'm new to this so I'm sorry if this is abit warbled!...

We have a normal subgroup N of a finite group H such that [H:N]=2
We have a chatacter Chi belonging to the irreducible characters of H, Irr(H) , which is zero on H\N.

I have already shown that Chi restricted to N = Theta 1 + Theta 2, Where
Theta 1 is not equal to Theta 2, and both Theta 1, and Theta 2 belong to Irr(N).

I am now trying to show that given a conjugacy class K of H which is also a conjugacy class of N, we get Theta 1 (n) = Theta 2 (n) for n a member of K.

Intuitively, I can see this is true, I have seen examples in the alternating group A6, the normal subgroup of index 2 in S6 fro example.

I would be really greatful for a push in the right direction...I have books: 'James and Liebeck' and 'Isaacs'... if you could even direct me to some relevant info?

Wow, think my notation is abit crap, sorry.
 
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It is traditional (though not necessarily ideal) to use ascii-tex to write maths in electronic form if you're not going to use the LaTeX capabilities of this site.

Thus \theta_1 is written as theta_1 (or \theta_1).

_ means subscript and ^ means superscript.

Right. I don't know if you're supposed to do it this way but here's my idea.

Consider Ind_N^H(theta_1).
 
Thanks for the notation tip, don't know how to use LaTeX so will try the other method.
Ok, I'm looking at Ind_N^H(theta_1), using Frobenius Reciprocity, I have <Ind_N^H(theta_1) , Chi> = <theta_1, Chi_N> (where < , > denotes inner product)

Since Chi_N = theta_1 + theta_2 we get <Ind_N^H(theta_1) , Chi> = <theta_1, theta_1 + theta_2>

now, is <theta_1, theta_1 + theta_2> = <theta_1, theta_1> + < theta_1, theta_2> ? and where can i go from here to get to my result...as in have theta_1(n) = theta_2(n) for each n belonging to the conjugacy class K
 
It's an inner product - it is of course (conjugate) linear in each variable. You have possibly learned (and I was assuming you had) that irreducible characters form an orthonormal basis of the class functions. However, if you didn't know that <A+B,C>=<A,C>+<B,C> then I have perhaps made a mistake in where you've got to in learning the material.

To get the final result you just need to look at how to construct in induced character.
 

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