Charged particle oscillation about the origin

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SUMMARY

The discussion centers on the oscillation of a positively charged ion in a static electric field defined by the equation ##E = -kz##, where ##k>0##. The ion oscillates according to the equation ##z = z_0cos(\omega t)##, and the field observed by the ion in its rest frame is indeed ##-kz_0 cos(\omega t)##. The field's amplitude remains constant, but its value varies with time due to the oscillation of the ion. The analysis primarily considers electrostatic fields, ignoring magnetic effects and relativity, and emphasizes the validity of the dipole approximation in the near-field zone.

PREREQUISITES
  • Understanding of electrostatic fields and their equations, specifically ##E = -kz##.
  • Familiarity with oscillatory motion represented by equations like ##z = z_0cos(\omega t)##.
  • Knowledge of reference frames in physics, particularly lab frame versus rest frame.
  • Basic concepts of electromagnetic waves and the dipole approximation.
NEXT STEPS
  • Study the dipole approximation in more detail, particularly its applications in electrostatics.
  • Learn about the near-field zone and its significance in electromagnetic theory.
  • Explore the relationship between oscillating charges and electromagnetic radiation.
  • Investigate the effects of relativistic speeds on charged particle motion in electric fields.
USEFUL FOR

Physicists, electrical engineers, and students studying electromagnetism, particularly those interested in charged particle dynamics and electrostatic fields.

kelly0303
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Hello! This is probably something simple but I am getting confused about it. Assume we have an electric field along the z axis given by ##E = -kz##, with ##k>0##, so the field on both sides of the xy-plane points towards the origin. Let's say that we have a positively charged ion at the origin and we give it a kick upwards such that it now oscillates as ##z = z_0cos(\omega t)##. What is the field that the ion sees in its rest frame (assume the ion is fixed on the z axis so we can ignore magnetic fields and it moves at nonrelativistic velocities)? Is it ##-kz_0 cos(\omega t)##? My main confusion is: does the amplitude of the field that the ion sees is constant or not?
 
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kelly0303 said:
assume the ion is fixed on the z axis
I don’t understand this comment. In its own rest frame shouldn’t the ion be fixed at the origin? Can you clarify the reference frame you are describing?
 
Dale said:
I don’t understand this comment. In its own rest frame shouldn’t the ion be fixed at the origin? Can you clarify the reference frame you are describing?
Sorry, I meant the ion is constrained to move on the z axis in the lab frame. Basically this is a 1D problem in the lab frame (in its rest frame the ion is always at the origin).
 
kelly0303 said:
Sorry, I meant the ion is constrained to move on the z axis in the lab frame. Basically this is a 1D problem in the lab frame (in its rest frame the ion is always at the origin).
Seems simple enough. Ignoring magnetism and relativity (i.e. considering only a fixed electrostatic field) and using a coordinate system anchored to the ion then you have an electrostatic field that varies both linearly with position and periodically with time.

The field value locally (right at the origin/right at the ion) will, of course, vary with time alone. It is the field values elsewhere which will vary with time and with their offset from the origin/ion.
 
But that's a pretty incomplete picture since you get in any case electromagnetic waves. The approximation to only consider the static fields is valid in the near-field zone, i.e., at distances close to the particle, where close means at distances much smaller than the wavelength of the radiation, ##\lambda=f/c##, were ##f## is the frequency of the oscillation.

The most simple approximate solution for this problem is the dipole approximation:

https://en.wikipedia.org/wiki/Dipole_antenna#Hertzian_dipole
 
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