Beer-monster
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I'm trying to "sure"up my Quantum Mechanics and found an sheet of mostly conceptual review questions. A sort of "Quantum minima".
I'd like to check my answers to a couple of these.
Firstly:
In terms of state vector the wavefunction is the expansion coefficient (probability amplitude) of a state i.e
[tex]\psi = \langle x \left | \psi \right\rangle[/tex]
What happens if you put an operator (e.g. p) between the bra and ket as if you were calculating an expectation value? i.e.
[tex]\left\langle x \left | p \right | \psi \right \rangle[/tex]
My guess is that the action of the operator on the state vector [itex]\left|\psi\right\rangle[/itex] will collapse the vector to a single basis vector of p [itex]\left| p \right\rangle[/itex] the expression above would reduce to an element of a basis transformation matrix [itex]\left\langle x | p \right\rangle[/itex]
Is that correct...at least in part?
I'd like to check my answers to a couple of these.
Firstly:
In terms of state vector the wavefunction is the expansion coefficient (probability amplitude) of a state i.e
[tex]\psi = \langle x \left | \psi \right\rangle[/tex]
What happens if you put an operator (e.g. p) between the bra and ket as if you were calculating an expectation value? i.e.
[tex]\left\langle x \left | p \right | \psi \right \rangle[/tex]
My guess is that the action of the operator on the state vector [itex]\left|\psi\right\rangle[/itex] will collapse the vector to a single basis vector of p [itex]\left| p \right\rangle[/itex] the expression above would reduce to an element of a basis transformation matrix [itex]\left\langle x | p \right\rangle[/itex]
Is that correct...at least in part?
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